18x2+7x-17=0

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Solution for 18x2+7x-17=0 equation:



18x^2+7x-17=0
a = 18; b = 7; c = -17;
Δ = b2-4ac
Δ = 72-4·18·(-17)
Δ = 1273
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{1273}}{2*18}=\frac{-7-\sqrt{1273}}{36} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{1273}}{2*18}=\frac{-7+\sqrt{1273}}{36} $

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