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18x^2-33x-216=0
a = 18; b = -33; c = -216;
Δ = b2-4ac
Δ = -332-4·18·(-216)
Δ = 16641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16641}=129$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-129}{2*18}=\frac{-96}{36} =-2+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+129}{2*18}=\frac{162}{36} =4+1/2 $
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