18x2-98=0

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Solution for 18x2-98=0 equation:



18x^2-98=0
a = 18; b = 0; c = -98;
Δ = b2-4ac
Δ = 02-4·18·(-98)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*18}=\frac{-84}{36} =-2+1/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*18}=\frac{84}{36} =2+1/3 $

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