18x2=42

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Solution for 18x2=42 equation:



18x^2=42
We move all terms to the left:
18x^2-(42)=0
a = 18; b = 0; c = -42;
Δ = b2-4ac
Δ = 02-4·18·(-42)
Δ = 3024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{3024}=\sqrt{144*21}=\sqrt{144}*\sqrt{21}=12\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{21}}{2*18}=\frac{0-12\sqrt{21}}{36} =-\frac{12\sqrt{21}}{36} =-\frac{\sqrt{21}}{3} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{21}}{2*18}=\frac{0+12\sqrt{21}}{36} =\frac{12\sqrt{21}}{36} =\frac{\sqrt{21}}{3} $

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