18y+10=40+3y

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Solution for 18y+10=40+3y equation: 



18y+10=40+3y

We move all terms to the left:

18y+10-(40+3y)=0

We add all the numbers together, and all the variables

18y-(3y+40)+10=0

We get rid of parentheses

18y-3y-40+10=0

We add all the numbers together, and all the variables

15y-30=0

We move all terms containing y to the left, all other terms to the right

15y=30

y=30/15

y=2

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