18y-(2y-4)=6(6-5y)-2(2-2y)

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Solution for 18y-(2y-4)=6(6-5y)-2(2-2y) equation: 



18y-(2y-4)=6(6-5y)-2(2-2y)

We move all terms to the left:

18y-(2y-4)-(6(6-5y)-2(2-2y))=0

We add all the numbers together, and all the variables

18y-(2y-4)-(6(-5y+6)-2(-2y+2))=0

We get rid of parentheses

18y-2y-(6(-5y+6)-2(-2y+2))+4=0



We calculate terms in parentheses: -(6(-5y+6)-2(-2y+2)), so:

6(-5y+6)-2(-2y+2)

We multiply parentheses

-30y+4y+36-4

We add all the numbers together, and all the variables

-26y+32

Back to the equation:

-(-26y+32)



We add all the numbers together, and all the variables

16y-(-26y+32)+4=0

We get rid of parentheses

16y+26y-32+4=0

We add all the numbers together, and all the variables

42y-28=0

We move all terms containing y to the left, all other terms to the right

42y=28

y=28/42

y=2/3

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