18y-6=11(y+2)+y

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Solution for 18y-6=11(y+2)+y equation: 



18y-6=11(y+2)+y

We move all terms to the left:

18y-6-(11(y+2)+y)=0



We calculate terms in parentheses: -(11(y+2)+y), so:

11(y+2)+y

We add all the numbers together, and all the variables

y+11(y+2)

We multiply parentheses

y+11y+22

We add all the numbers together, and all the variables

12y+22

Back to the equation:

-(12y+22)



We get rid of parentheses

18y-12y-22-6=0

We add all the numbers together, and all the variables

6y-28=0

We move all terms containing y to the left, all other terms to the right

6y=28

y=28/6

y=4+2/3

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