18y-6y+22=11(y+2)+y

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Solution for 18y-6y+22=11(y+2)+y equation: 



18y-6y+22=11(y+2)+y

We move all terms to the left:

18y-6y+22-(11(y+2)+y)=0

We add all the numbers together, and all the variables

12y-(11(y+2)+y)+22=0



We calculate terms in parentheses: -(11(y+2)+y), so:

11(y+2)+y

We add all the numbers together, and all the variables

y+11(y+2)

We multiply parentheses

y+11y+22

We add all the numbers together, and all the variables

12y+22

Back to the equation:

-(12y+22)



We get rid of parentheses

12y-12y-22+22=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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