18y-6y=11(y+2)=y

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Solution for 18y-6y=11(y+2)=y equation: 



18y-6y=11(y+2)=y

We move all terms to the left:

18y-6y-(11(y+2))=0

We add all the numbers together, and all the variables

12y-(11(y+2))=0



We calculate terms in parentheses: -(11(y+2)), so:

11(y+2)

We multiply parentheses

11y+22

Back to the equation:

-(11y+22)



We get rid of parentheses

12y-11y-22=0

We add all the numbers together, and all the variables

y-22=0

We move all terms containing y to the left, all other terms to the right

y=22

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