18y-6y=11(y+2)y

Solution for 18y-6y=11(y+2)y equation:

18y-6y=11(y+2)y

We move all terms to the left:

18y-6y-(11(y+2)y)=0

We add all the numbers together, and all the variables

12y-(11(y+2)y)=0


We calculate terms in parentheses: -(11(y+2)y), so:

11(y+2)y

We multiply parentheses

11y^2+22y

Back to the equation:

-(11y^2+22y)


We get rid of parentheses

-11y^2+12y-22y=0

We add all the numbers together, and all the variables

-11y^2-10y=0

a = -11; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·(-11)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*-11}=\frac{0}{-22}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*-11}=\frac{20}{-22}
=-10/11
$