18z+3z+3z+2z+6z=20

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Solution for 18z+3z+3z+2z+6z=20 equation:



18z+3z+3z+2z+6z=20
We move all terms to the left:
18z+3z+3z+2z+6z-(20)=0
We add all the numbers together, and all the variables
32z-20=0
We move all terms containing z to the left, all other terms to the right
32z=20
z=20/32
z=5/8

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