18z+3z+3z+2z+6z=20

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Solution for 18z+3z+3z+2z+6z=20 equation: 



18z+3z+3z+2z+6z=20

We move all terms to the left:

18z+3z+3z+2z+6z-(20)=0

We add all the numbers together, and all the variables

32z-20=0

We move all terms containing z to the left, all other terms to the right

32z=20

z=20/32

z=5/8

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