19(3d-4)+100=62

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Solution for 19(3d-4)+100=62 equation: 



19(3d-4)+100=62

We move all terms to the left:

19(3d-4)+100-(62)=0

We add all the numbers together, and all the variables

19(3d-4)+38=0

We multiply parentheses

57d-76+38=0

We add all the numbers together, and all the variables

57d-38=0

We move all terms containing d to the left, all other terms to the right

57d=38

d=38/57

d=2/3

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