19(v+3)-3v=4(4v+2)-12

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Solution for 19(v+3)-3v=4(4v+2)-12 equation: 



19(v+3)-3v=4(4v+2)-12

We move all terms to the left:

19(v+3)-3v-(4(4v+2)-12)=0

We add all the numbers together, and all the variables

-3v+19(v+3)-(4(4v+2)-12)=0

We multiply parentheses

-3v+19v-(4(4v+2)-12)+57=0



We calculate terms in parentheses: -(4(4v+2)-12), so:

4(4v+2)-12

We multiply parentheses

16v+8-12

We add all the numbers together, and all the variables

16v-4

Back to the equation:

-(16v-4)



We add all the numbers together, and all the variables

16v-(16v-4)+57=0

We get rid of parentheses

16v-16v+4+57=0

We add all the numbers together, and all the variables

61!=0

There is no solution for this equation

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