19(x-12)=6(2x-2)

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Solution for 19(x-12)=6(2x-2) equation: 



19(x-12)=6(2x-2)

We move all terms to the left:

19(x-12)-(6(2x-2))=0

We multiply parentheses

19x-(6(2x-2))-228=0



We calculate terms in parentheses: -(6(2x-2)), so:

6(2x-2)

We multiply parentheses

12x-12

Back to the equation:

-(12x-12)



We get rid of parentheses

19x-12x+12-228=0

We add all the numbers together, and all the variables

7x-216=0

We move all terms containing x to the left, all other terms to the right

7x=216

x=216/7

x=30+6/7

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