19+(3-5x)-(1-x)=3x-2(x-3)

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Solution for 19+(3-5x)-(1-x)=3x-2(x-3) equation: 



19+(3-5x)-(1-x)=3x-2(x-3)

We move all terms to the left:

19+(3-5x)-(1-x)-(3x-2(x-3))=0

We add all the numbers together, and all the variables

(-5x+3)-(-1x+1)-(3x-2(x-3))+19=0

We get rid of parentheses

-5x+1x-(3x-2(x-3))+3-1+19=0



We calculate terms in parentheses: -(3x-2(x-3)), so:

3x-2(x-3)

We multiply parentheses

3x-2x+6

We add all the numbers together, and all the variables

x+6

Back to the equation:

-(x+6)



We add all the numbers together, and all the variables

-4x-(x+6)+21=0

We get rid of parentheses

-4x-x-6+21=0

We add all the numbers together, and all the variables

-5x+15=0

We move all terms containing x to the left, all other terms to the right

-5x=-15

x=-15/-5

x=+3

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