19+(5x+1)=(9x-3)*2

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Solution for 19+(5x+1)=(9x-3)*2 equation: 



19+(5x+1)=(9x-3)*2

We move all terms to the left:

19+(5x+1)-((9x-3)*2)=0

We get rid of parentheses

5x-((9x-3)*2)+1+19=0



We calculate terms in parentheses: -((9x-3)*2), so:

(9x-3)*2

We multiply parentheses

18x-6

Back to the equation:

-(18x-6)



We add all the numbers together, and all the variables

5x-(18x-6)+20=0

We get rid of parentheses

5x-18x+6+20=0

We add all the numbers together, and all the variables

-13x+26=0

We move all terms containing x to the left, all other terms to the right

-13x=-26

x=-26/-13

x=+2

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