19+(5x+1)=(9x-3)*2

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Solution for 19+(5x+1)=(9x-3)*2 equation:



19+(5x+1)=(9x-3)*2
We move all terms to the left:
19+(5x+1)-((9x-3)*2)=0
We get rid of parentheses
5x-((9x-3)*2)+1+19=0
We calculate terms in parentheses: -((9x-3)*2), so:
(9x-3)*2
We multiply parentheses
18x-6
Back to the equation:
-(18x-6)
We add all the numbers together, and all the variables
5x-(18x-6)+20=0
We get rid of parentheses
5x-18x+6+20=0
We add all the numbers together, and all the variables
-13x+26=0
We move all terms containing x to the left, all other terms to the right
-13x=-26
x=-26/-13
x=+2

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