19+(5x+1)=(9x-3)/2

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Solution for 19+(5x+1)=(9x-3)/2 equation:



19+(5x+1)=(9x-3)/2
We move all terms to the left:
19+(5x+1)-((9x-3)/2)=0
We get rid of parentheses
5x-((9x-3)/2)+1+19=0
We multiply all the terms by the denominator
5x*2)-((9x-3)+1*2)+19*2)=0
We add all the numbers together, and all the variables
5x*2)-((9x-3)=0
Wy multiply elements
10x^2=0
a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{20}=0$

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