19+1/4z=40

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Solution for 19+1/4z=40 equation: 



19+1/4z=40

We move all terms to the left:

19+1/4z-(40)=0



Domain of the equation: 4z!=0

z!=0/4

z!=0

z∈R



We add all the numbers together, and all the variables

1/4z-21=0

We multiply all the terms by the denominator


-21*4z+1=0

Wy multiply elements

-84z+1=0

We move all terms containing z to the left, all other terms to the right

-84z=-1

z=-1/-84

z=1/84

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