19+2(x-23)=3(x-19)

Solution for 19+2(x-23)=3(x-19) equation:

19+2(x-23)=3(x-19)

We move all terms to the left:

19+2(x-23)-(3(x-19))=0

We multiply parentheses

2x-(3(x-19))-46+19=0


We calculate terms in parentheses: -(3(x-19)), so:

3(x-19)

We multiply parentheses

3x-57

Back to the equation:

-(3x-57)


We add all the numbers together, and all the variables

2x-(3x-57)-27=0

We get rid of parentheses

2x-3x+57-27=0

We add all the numbers together, and all the variables

-1x+30=0

We move all terms containing x to the left, all other terms to the right

-x=-30

x=-30/-1

x=+30