19+2(x-23)=3(x-19)

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Solution for 19+2(x-23)=3(x-19) equation:



19+2(x-23)=3(x-19)
We move all terms to the left:
19+2(x-23)-(3(x-19))=0
We multiply parentheses
2x-(3(x-19))-46+19=0
We calculate terms in parentheses: -(3(x-19)), so:
3(x-19)
We multiply parentheses
3x-57
Back to the equation:
-(3x-57)
We add all the numbers together, and all the variables
2x-(3x-57)-27=0
We get rid of parentheses
2x-3x+57-27=0
We add all the numbers together, and all the variables
-1x+30=0
We move all terms containing x to the left, all other terms to the right
-x=-30
x=-30/-1
x=+30

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