19+3b=-(1-7b)+6b

Solution for 19+3b=-(1-7b)+6b equation:

19+3b=-(1-7b)+6b

We move all terms to the left:

19+3b-(-(1-7b)+6b)=0

We add all the numbers together, and all the variables

3b-(-(-7b+1)+6b)+19=0


We calculate terms in parentheses: -(-(-7b+1)+6b), so:

-(-7b+1)+6b

We add all the numbers together, and all the variables

6b-(-7b+1)

We get rid of parentheses

6b+7b-1

We add all the numbers together, and all the variables

13b-1

Back to the equation:

-(13b-1)


We get rid of parentheses

3b-13b+1+19=0

We add all the numbers together, and all the variables

-10b+20=0

We move all terms containing b to the left, all other terms to the right

-10b=-20

b=-20/-10

b=+2