19+3x=2(-x+5)-21

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Solution for 19+3x=2(-x+5)-21 equation: 



19+3x=2(-x+5)-21

We move all terms to the left:

19+3x-(2(-x+5)-21)=0

We add all the numbers together, and all the variables

3x-(2(-1x+5)-21)+19=0



We calculate terms in parentheses: -(2(-1x+5)-21), so:

2(-1x+5)-21

We multiply parentheses

-2x+10-21

We add all the numbers together, and all the variables

-2x-11

Back to the equation:

-(-2x-11)



We get rid of parentheses

3x+2x+11+19=0

We add all the numbers together, and all the variables

5x+30=0

We move all terms containing x to the left, all other terms to the right

5x=-30

x=-30/5

x=-6

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