19+3x=2(-x+9)-39

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Solution for 19+3x=2(-x+9)-39 equation: 



19+3x=2(-x+9)-39

We move all terms to the left:

19+3x-(2(-x+9)-39)=0

We add all the numbers together, and all the variables

3x-(2(-1x+9)-39)+19=0



We calculate terms in parentheses: -(2(-1x+9)-39), so:

2(-1x+9)-39

We multiply parentheses

-2x+18-39

We add all the numbers together, and all the variables

-2x-21

Back to the equation:

-(-2x-21)



We get rid of parentheses

3x+2x+21+19=0

We add all the numbers together, and all the variables

5x+40=0

We move all terms containing x to the left, all other terms to the right

5x=-40

x=-40/5

x=-8

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