19+3y-4=12y-10-4y

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Solution for 19+3y-4=12y-10-4y equation: 



19+3y-4=12y-10-4y

We move all terms to the left:

19+3y-4-(12y-10-4y)=0

We add all the numbers together, and all the variables

3y-(8y-10)+19-4=0

We add all the numbers together, and all the variables

3y-(8y-10)+15=0

We get rid of parentheses

3y-8y+10+15=0

We add all the numbers together, and all the variables

-5y+25=0

We move all terms containing y to the left, all other terms to the right

-5y=-25

y=-25/-5

y=+5

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