19-(2x+3)=2(x+3)+x=

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Solution for 19-(2x+3)=2(x+3)+x= equation: 



19-(2x+3)=2(x+3)+x=

We move all terms to the left:

19-(2x+3)-(2(x+3)+x)=0

We get rid of parentheses

-2x-(2(x+3)+x)-3+19=0



We calculate terms in parentheses: -(2(x+3)+x), so:

2(x+3)+x

We add all the numbers together, and all the variables

x+2(x+3)

We multiply parentheses

x+2x+6

We add all the numbers together, and all the variables

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

-2x-(3x+6)+16=0

We get rid of parentheses

-2x-3x-6+16=0

We add all the numbers together, and all the variables

-5x+10=0

We move all terms containing x to the left, all other terms to the right

-5x=-10

x=-10/-5

x=+2

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