19-(2x+3)=2(x+3)+xx=

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Solution for 19-(2x+3)=2(x+3)+xx= equation: 



19-(2x+3)=2(x+3)+xx=

We move all terms to the left:

19-(2x+3)-(2(x+3)+xx)=0

We get rid of parentheses

-2x-(2(x+3)+xx)-3+19=0



We calculate terms in parentheses: -(2(x+3)+xx), so:

2(x+3)+xx

We multiply parentheses

2x+xx+6

Back to the equation:

-(2x+xx+6)



We add all the numbers together, and all the variables

-2x-(2x+xx+6)+16=0

We get rid of parentheses

-2x-2x-xx-6+16=0

We add all the numbers together, and all the variables

-4x-xx+10=0

We move all terms containing x to the left, all other terms to the right

-4x-xx=-10

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