19-15(3x+1)=36-6(5x-3)-5(x+7)

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Solution for 19-15(3x+1)=36-6(5x-3)-5(x+7) equation: 



19-15(3x+1)=36-6(5x-3)-5(x+7)

We move all terms to the left:

19-15(3x+1)-(36-6(5x-3)-5(x+7))=0

We multiply parentheses

-45x-(36-6(5x-3)-5(x+7))-15+19=0



We calculate terms in parentheses: -(36-6(5x-3)-5(x+7)), so:

36-6(5x-3)-5(x+7)

determiningTheFunctionDomain
-6(5x-3)-5(x+7)+36

We multiply parentheses

-30x-5x+18-35+36

We add all the numbers together, and all the variables

-35x+19

Back to the equation:

-(-35x+19)



We add all the numbers together, and all the variables

-45x-(-35x+19)+4=0

We get rid of parentheses

-45x+35x-19+4=0

We add all the numbers together, and all the variables

-10x-15=0

We move all terms containing x to the left, all other terms to the right

-10x=15

x=15/-10

x=-1+1/2

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