19-2(3x-1)/5=x+2

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Solution for 19-2(3x-1)/5=x+2 equation: 


x in (-oo:+oo)

19-((2*(3*x-1))/5) = x+2 // - x+2

19-((2*(3*x-1))/5)-x-2 = 0

(-2/5)*(3*x-1)-x-2+19 = 0

19-2/5*(3*x-1)-x-2 = 0

19-2/5*(3*x-1)-x-2 = 0

2/5-11/5*x-2+19 = 0

19-11/5*x-8/5 = 0

87/5-11/5*x = 0

87/5-11/5*x = 0

87/5-11/5*x = 0 // - 87/5

-11/5*x = -87/5 // : -11/5

x = -87/5/(-11/5)

x = 87/11

x = 87/11

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