19-2(3x-1)/5=x=2

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Solution for 19-2(3x-1)/5=x=2 equation:



19-2(3x-1)/5=x=2
We move all terms to the left:
19-2(3x-1)/5-(x)=0
We add all the numbers together, and all the variables
-1x-2(3x-1)/5+19=0
We multiply all the terms by the denominator
-1x*5-2(3x-1)+19*5=0
We add all the numbers together, and all the variables
-1x*5-2(3x-1)+95=0
We multiply parentheses
-1x*5-6x+2+95=0
Wy multiply elements
-5x-6x+2+95=0
We add all the numbers together, and all the variables
-11x+97=0
We move all terms containing x to the left, all other terms to the right
-11x=-97
x=-97/-11
x=8+9/11

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