19-2(3x-1)=x+12

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Solution for 19-2(3x-1)=x+12 equation: 



19-2(3x-1)=x+12

We move all terms to the left:

19-2(3x-1)-(x+12)=0

We multiply parentheses

-6x-(x+12)+2+19=0

We get rid of parentheses

-6x-x-12+2+19=0

We add all the numbers together, and all the variables

-7x+9=0

We move all terms containing x to the left, all other terms to the right

-7x=-9

x=-9/-7

x=1+2/7

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