19-3(2u+7)=4(2+u)

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Solution for 19-3(2u+7)=4(2+u) equation: 



19-3(2u+7)=4(2+u)

We move all terms to the left:

19-3(2u+7)-(4(2+u))=0

We add all the numbers together, and all the variables

-3(2u+7)-(4(u+2))+19=0

We multiply parentheses

-6u-(4(u+2))-21+19=0



We calculate terms in parentheses: -(4(u+2)), so:

4(u+2)

We multiply parentheses

4u+8

Back to the equation:

-(4u+8)



We add all the numbers together, and all the variables

-6u-(4u+8)-2=0

We get rid of parentheses

-6u-4u-8-2=0

We add all the numbers together, and all the variables

-10u-10=0

We move all terms containing u to the left, all other terms to the right

-10u=10

u=10/-10

u=-1

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