19.6x-4.9x2=0

Solution for 19.6x-4.9x2=0 equation:

19.6x-4.9x^2=0

a = -4.9; b = 19.6; c = 0;
Δ = b2-4ac
Δ = 19.62-4·(-4.9)·0
Δ = 384.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19.6)-\sqrt{384.16}}{2*-4.9}=\frac{-19.6-\sqrt{384.16}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19.6)+\sqrt{384.16}}{2*-4.9}=\frac{-19.6+\sqrt{384.16}}{-9.8}
$