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19/2x+4/5=11/2x
We move all terms to the left:
19/2x+4/5-(11/2x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
19/2x-(+11/2x)+4/5=0
We get rid of parentheses
19/2x-11/2x+4/5=0
We calculate fractions
There is no solution for this equation
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