19/3x+6=12

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Solution for 19/3x+6=12 equation:



19/3x+6=12
We move all terms to the left:
19/3x+6-(12)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
19/3x-6=0
We multiply all the terms by the denominator
-6*3x+19=0
Wy multiply elements
-18x+19=0
We move all terms containing x to the left, all other terms to the right
-18x=-19
x=-19/-18
x=1+1/18

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