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190=1.5b^2
We move all terms to the left:
190-(1.5b^2)=0
We get rid of parentheses
-1.5b^2+190=0
a = -1.5; b = 0; c = +190;
Δ = b2-4ac
Δ = 02-4·(-1.5)·190
Δ = 1140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1140}=\sqrt{4*285}=\sqrt{4}*\sqrt{285}=2\sqrt{285}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{285}}{2*-1.5}=\frac{0-2\sqrt{285}}{-3} =-\frac{2\sqrt{285}}{-3} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{285}}{2*-1.5}=\frac{0+2\sqrt{285}}{-3} =\frac{2\sqrt{285}}{-3} $
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