192=2(2/3l+l)

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Solution for 192=2(2/3l+l) equation: 



192=2(2/3l+l)

We move all terms to the left:

192-(2(2/3l+l))=0



Domain of the equation: 3l+l))!=0

l∈R



We add all the numbers together, and all the variables

-(2(+l+2/3l))+192=0

We multiply all the terms by the denominator


-(2(+l+2+192*3l))=0



We calculate terms in parentheses: -(2(+l+2+192*3l)), so:

2(+l+2+192*3l)

We add all the numbers together, and all the variables

2(l+192*3l+2)

We multiply parentheses

2l+1152l+4

We add all the numbers together, and all the variables

1154l+4

Back to the equation:

-(1154l+4)



We get rid of parentheses

-1154l-4=0

We move all terms containing l to the left, all other terms to the right

-1154l=4

l=4/-1154

l=-2/577

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