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192=3h*h
We move all terms to the left:
192-(3h*h)=0
We add all the numbers together, and all the variables
-(+3h*h)+192=0
We get rid of parentheses
-3h*h+192=0
Wy multiply elements
-3h^2+192=0
a = -3; b = 0; c = +192;
Δ = b2-4ac
Δ = 02-4·(-3)·192
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*-3}=\frac{-48}{-6} =+8 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*-3}=\frac{48}{-6} =-8 $
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