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192=3w^2
We move all terms to the left:
192-(3w^2)=0
a = -3; b = 0; c = +192;
Δ = b2-4ac
Δ = 02-4·(-3)·192
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*-3}=\frac{-48}{-6} =+8 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*-3}=\frac{48}{-6} =-8 $
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