192=3w2

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Solution for 192=3w2 equation:



192=3w^2
We move all terms to the left:
192-(3w^2)=0
a = -3; b = 0; c = +192;
Δ = b2-4ac
Δ = 02-4·(-3)·192
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*-3}=\frac{-48}{-6} =+8 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*-3}=\frac{48}{-6} =-8 $

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