1953=31(p+25)

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Solution for 1953=31(p+25) equation: 



1953=31(p+25)

We move all terms to the left:

1953-(31(p+25))=0



We calculate terms in parentheses: -(31(p+25)), so:

31(p+25)

We multiply parentheses

31p+775

Back to the equation:

-(31p+775)



We get rid of parentheses

-31p-775+1953=0

We add all the numbers together, and all the variables

-31p+1178=0

We move all terms containing p to the left, all other terms to the right

-31p=-1178

p=-1178/-31

p=+38

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