19683=x2

Solution for 19683=x2 equation:

19683=x2

We move all terms to the left:

19683-(x2)=0

We add all the numbers together, and all the variables

-1x^2+19683=0

a = -1; b = 0; c = +19683;
Δ = b2-4ac
Δ = 02-4·(-1)·19683
Δ = 78732
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{78732}=\sqrt{26244*3}=\sqrt{26244}*\sqrt{3}=162\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-162\sqrt{3}}{2*-1}=\frac{0-162\sqrt{3}}{-2}
=-\frac{162\sqrt{3}}{-2}
=-\frac{81\sqrt{3}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+162\sqrt{3}}{2*-1}=\frac{0+162\sqrt{3}}{-2}
=\frac{162\sqrt{3}}{-2}
=\frac{81\sqrt{3}}{-1}
$