196=(2x+6)(2x+6)

Solution for 196=(2x+6)(2x+6) equation:

196=(2x+6)(2x+6)

We move all terms to the left:

196-((2x+6)(2x+6))=0

We multiply parentheses ..

-((+4x^2+12x+12x+36))+196=0


We calculate terms in parentheses: -((+4x^2+12x+12x+36)), so:

(+4x^2+12x+12x+36)

We get rid of parentheses

4x^2+12x+12x+36

We add all the numbers together, and all the variables

4x^2+24x+36

Back to the equation:

-(4x^2+24x+36)


We get rid of parentheses

-4x^2-24x-36+196=0

We add all the numbers together, and all the variables

-4x^2-24x+160=0

a = -4; b = -24; c = +160;
Δ = b2-4ac
Δ = -242-4·(-4)·160
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-56}{2*-4}=\frac{-32}{-8}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+56}{2*-4}=\frac{80}{-8}
=-10
$