196x2+196x=200x2

Solution for 196x2+196x=200x2 equation:

196x^2+196x=200x^2

We move all terms to the left:

196x^2+196x-(200x^2)=0

determiningTheFunctionDomain
196x^2-200x^2+196x=0

We add all the numbers together, and all the variables

-4x^2+196x=0

a = -4; b = 196; c = 0;
Δ = b2-4ac
Δ = 1962-4·(-4)·0
Δ = 38416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{38416}=196$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(196)-196}{2*-4}=\frac{-392}{-8}
=+49
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(196)+196}{2*-4}=\frac{0}{-8}
=0
$