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196x^2-49=0
a = 196; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·196·(-49)
Δ = 38416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{38416}=196$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-196}{2*196}=\frac{-196}{392} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+196}{2*196}=\frac{196}{392} =1/2 $
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