1980=(330+15x)(6-0.25x)

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Solution for 1980=(330+15x)(6-0.25x) equation:



1980=(330+15x)(6-0.25x)
We move all terms to the left:
1980-((330+15x)(6-0.25x))=0
We add all the numbers together, and all the variables
-((15x+330)(-0.25x+6))+1980=0
We multiply parentheses ..
-((+0x^2+90x+0x+1980))+1980=0
We calculate terms in parentheses: -((+0x^2+90x+0x+1980)), so:
(+0x^2+90x+0x+1980)
We get rid of parentheses
0x^2+90x+0x+1980
We add all the numbers together, and all the variables
x^2+91x+1980
Back to the equation:
-(x^2+91x+1980)
We get rid of parentheses
-x^2-91x-1980+1980=0
We add all the numbers together, and all the variables
-1x^2-91x=0
a = -1; b = -91; c = 0;
Δ = b2-4ac
Δ = -912-4·(-1)·0
Δ = 8281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8281}=91$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-91)-91}{2*-1}=\frac{0}{-2} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-91)+91}{2*-1}=\frac{182}{-2} =-91 $

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