19=(18x+24)/6+3(2x-1)

Solution for 19=(18x+24)/6+3(2x-1) equation:

19=(18x+24)/6+3(2x-1)

We move all terms to the left:

19-((18x+24)/6+3(2x-1))=0


Domain of the equation: 6+3(2x-1))!=0

We move all terms containing x to the left, all other terms to the right

3(2x-1))!=-6

x∈R


We multiply all the terms by the denominator


-((18x+24)+19*6+3(2x-1))=0


We calculate terms in parentheses: -((18x+24)+19*6+3(2x-1)), so:

(18x+24)+19*6+3(2x-1)

determiningTheFunctionDomain
(18x+24)+3(2x-1)+19*6

We add all the numbers together, and all the variables

(18x+24)+3(2x-1)+114

We multiply parentheses

(18x+24)+6x-3+114

We get rid of parentheses

18x+6x+24-3+114

We add all the numbers together, and all the variables

24x+135

Back to the equation:

-(24x+135)


We get rid of parentheses

-24x-135=0

We move all terms containing x to the left, all other terms to the right

-24x=135

x=135/-24

x=-5+5/8