19=(z)/(3)+17

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Solution for 19=(z)/(3)+17 equation:



19=(z)/(3)+17
We move all terms to the left:
19-((z)/(3)+17)=0
We get rid of parentheses
-z/3-17+19=0
We multiply all the terms by the denominator
-z-17*3+19*3=0
We add all the numbers together, and all the variables
-1z+6=0
We move all terms containing z to the left, all other terms to the right
-z=-6
z=-6/-1
z=+6

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