19=(z)/(3)+17

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Solution for 19=(z)/(3)+17 equation: 



19=(z)/(3)+17

We move all terms to the left:

19-((z)/(3)+17)=0

We get rid of parentheses

-z/3-17+19=0

We multiply all the terms by the denominator


-z-17*3+19*3=0

We add all the numbers together, and all the variables

-1z+6=0

We move all terms containing z to the left, all other terms to the right

-z=-6

z=-6/-1

z=+6

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