19=-3(24-z)+2(z-2)

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Solution for 19=-3(24-z)+2(z-2) equation: 



19=-3(24-z)+2(z-2)

We move all terms to the left:

19-(-3(24-z)+2(z-2))=0

We add all the numbers together, and all the variables

-(-3(-1z+24)+2(z-2))+19=0



We calculate terms in parentheses: -(-3(-1z+24)+2(z-2)), so:

-3(-1z+24)+2(z-2)

We multiply parentheses

3z+2z-72-4

We add all the numbers together, and all the variables

5z-76

Back to the equation:

-(5z-76)



We get rid of parentheses

-5z+76+19=0

We add all the numbers together, and all the variables

-5z+95=0

We move all terms containing z to the left, all other terms to the right

-5z=-95

z=-95/-5

z=+19

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