19=2(j+4)+1

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Solution for 19=2(j+4)+1 equation: 



19=2(j+4)+1

We move all terms to the left:

19-(2(j+4)+1)=0



We calculate terms in parentheses: -(2(j+4)+1), so:

2(j+4)+1

We multiply parentheses

2j+8+1

We add all the numbers together, and all the variables

2j+9

Back to the equation:

-(2j+9)



We get rid of parentheses

-2j-9+19=0

We add all the numbers together, and all the variables

-2j+10=0

We move all terms containing j to the left, all other terms to the right

-2j=-10

j=-10/-2

j=+5

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