19=2-(c+5)

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Solution for 19=2-(c+5) equation:



19=2-(c+5)
We move all terms to the left:
19-(2-(c+5))=0
We calculate terms in parentheses: -(2-(c+5)), so:
2-(c+5)
determiningTheFunctionDomain -(c+5)+2
We get rid of parentheses
-c-5+2
We add all the numbers together, and all the variables
-1c-3
Back to the equation:
-(-1c-3)
We get rid of parentheses
1c+3+19=0
We add all the numbers together, and all the variables
c+22=0
We move all terms containing c to the left, all other terms to the right
c=-22

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