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19=2/5x+3
We move all terms to the left:
19-(2/5x+3)=0
Domain of the equation: 5x+3)!=0We get rid of parentheses
x∈R
-2/5x-3+19=0
We multiply all the terms by the denominator
-3*5x+19*5x-2=0
Wy multiply elements
-15x+95x-2=0
We add all the numbers together, and all the variables
80x-2=0
We move all terms containing x to the left, all other terms to the right
80x=2
x=2/80
x=1/40
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