19=3(u+2)+1

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Solution for 19=3(u+2)+1 equation: 



19=3(u+2)+1

We move all terms to the left:

19-(3(u+2)+1)=0



We calculate terms in parentheses: -(3(u+2)+1), so:

3(u+2)+1

We multiply parentheses

3u+6+1

We add all the numbers together, and all the variables

3u+7

Back to the equation:

-(3u+7)



We get rid of parentheses

-3u-7+19=0

We add all the numbers together, and all the variables

-3u+12=0

We move all terms containing u to the left, all other terms to the right

-3u=-12

u=-12/-3

u=+4

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